A Jar Contains 39 Red White And Blue Marbles

If x equals the number of red marbles drawn which of the following tables shows 3545377.

A jar contains 39 red white and blue marbles.

The probability of both happening would be 1 4 x 12 47. We could potential remove 8 marbles and there is a possibility they could all be red. Two marbles are drawn. We would need to remove 3 more marble to be absolutely certain there was at least three marbles of each color.

A jar contains 3 white 4 blue 5 red and 2 green marbles. Two marbles are drawn without replacement. A jar contains 3 white marbles 4 red marbles and 5 blue marbles. A are red b neither red or green c not white an ordinary pack of 77.

Next we could remove 7 more marbles and there is a possibility no matter how small they could all be blue. B find probabilities for p bb p br p rb p ww p at least one red p exactly one red 3. You would try different combinations such as 25 of each colored marble in a jar or putting all red marbles in one jar and all the blue in the other. For the second marble the probability of getting a red would be 12 47.

See a solution process below. You have 12 marbles total. Find the probability of choosing the given marbles without replacement. A draw the tree diagram for the experiment.

So the probability of drawing red is 3 12 or 1 4 reduced. And there are still 5 white marbles. 1 2 chance we pick jar a 50 50 chance we pick a red marble 1 2 chance we pick jar b 0 50 chance we pick a red marble. So to be absolutely certain you would have at least 3.

A jar contains a total of 20 marbles that are blue green or white. Asked 03 25 15 suppose a jar contains 11 red marbles and 37 blue marbles. For the first marble the probably of getting a red would be 12 48 which is 1 4. If you reach in the jar and pull out 2 marbles at random find the probability that both are red.

Two marbles are drawn without replacement from a jar containing 4 black and 6 white marbles. So the probability of white is 5 11. The number of white marbles is three more than the number of green marbles and the number of blue marbles is one more than twice the number of green marbles b g w 20 w g 3 b 2g 1 substitute for b and w and solve for g 2g 1 g g 3 20 4g 4 20 4g. You would still end up with a chance of 50.

Now if you take out one red marble then there are 11 now in the jar. A jar contains 2 red 1 white and 3 blue marbles. If a marble is drawn at random from the jar what is the probability that the marble.